Curvature of a parametric curve

Analytical expression
Let s:R→R3 be a vector valued function representing a parametric curve s(t) with t∈R the curve's parameter; the curvature of s is given by κ:R→R as follows:
κ(t)=‖
Where '×' is the cross product, s'(t) speed (velocity) at t , s''(t) the acceleration, and \| \ \| the Euclidean norm of a vector.
2D version
The 2D cross product is not a vector like the 3D cross product but a real value \mathbb R. In addition, the norm of the 2D cross product is the value of the cross product itself: \| s' \times s'' \| = s_x' s''_y - s_y's_x'' . Finally the 2D cross product can be expressed as the determinant \left | \phantom{x} \right | of the 2D matrix below:
\kappa(t) = \frac{ \left | \begin{matrix} s_x'(t) & s_x''(t) \\ s_y'(t) & s_y''(t) \\ \end{matrix} \right | }{ \| s'(t) \|^3 }Numerical computation
If you don't have the formula (i.e. analytical expression) of s(t), you can numerically compute it using finite differences:
with h "small" (ex h < 0.0001 )
Shader code
Glsl code to visualize the curvature:
shadertoy.com/view/Mlf3zl
// Under MIT License // Copyright © 2015 Inigo Quilez // Computes the curvature of a parametric curve f(x) as // c(f) = | f' x f''| / |f'|^3 // More info here: https://en.wikipedia.org/wiki/Curvature vec3 a, b, c, m, n; // parametric curve value s(t): vec3 mapD0(float t){ return 0.25 + a*cos(t+m)*(b+c*cos(t*7.0+n)); } // curve derivative (velocity) s'(t) vec3 mapD1(float t){ return -7.0*a*c*cos(t+m)*sin(7.0*t+n) - a*sin(t+m)*(b+c*cos(7.0*t+n)); } // curve second derivative (acceleration) s''(t) vec3 mapD2(float t){ return 14.0*a*c*sin(t+m)*sin(7.0*t+n) - a*cos(t+m)*(b+c*cos(7.0*t+n)) - 49.0*a*c*cos(t+m)*cos(7.0*t+n); } //---------------------------------------- float curvature( float t ){ vec3 r1 = mapD1(t); // first derivative vec3 r2 = mapD2(t); // second derivative return length(cross(r1,r2)) / pow(length(r1),3.0); } float curvature_reciprocal( float t ){ vec3 r1 = mapD1(t); // first derivative vec3 r2 = mapD2(t); // second derivative return pow(length(r1),3.0) / length(cross(r1,r2)); }
3d version: https://www.shadertoy.com/view/XlfXR4
Deriving the formula
A separate on article on how to interpret and derive the curvature formula where I do an in-depth explanation.
Related
- https://tutorial.math.lamar.edu/classes/calciii/curvature.aspx
- Khan Academy video series on curvature
- Khan Academy summary article on curvature
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